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Determine the point estimate of the population mean and margin of error for the confidence interval with lower bound 18 and upper bound: 32.


A) Determine the point estimate of the population mean and margin of error for the confidence interval with lower bound 18 and upper bound: 32. A)    =18, E=14 B)    =32, E=7 C)    =25, E=14 D)    =25, E=7 =18, E=14
B) Determine the point estimate of the population mean and margin of error for the confidence interval with lower bound 18 and upper bound: 32. A)    =18, E=14 B)    =32, E=7 C)    =25, E=14 D)    =25, E=7 =32, E=7
C) Determine the point estimate of the population mean and margin of error for the confidence interval with lower bound 18 and upper bound: 32. A)    =18, E=14 B)    =32, E=7 C)    =25, E=14 D)    =25, E=7 =25, E=14
D) Determine the point estimate of the population mean and margin of error for the confidence interval with lower bound 18 and upper bound: 32. A)    =18, E=14 B)    =32, E=7 C)    =25, E=14 D)    =25, E=7 =25, E=7

E) A) and D)
F) All of the above

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Determine the critical value Determine the critical value   that corresponds to the given level of confidence. -92% A)  1.41 B)  0.82 C)  1.45 D)  1.75 that corresponds to the given level of confidence. -92%


A) 1.41
B) 0.82
C) 1.45
D) 1.75

E) B) and C)
F) A) and B)

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Determine the critical value Determine the critical value   that corresponds to the given level of confidence. -97% A)  1.88 B)  1.92 C)  2.17 D)  0.83 that corresponds to the given level of confidence. -97%


A) 1.88
B) 1.92
C) 2.17
D) 0.83

E) B) and D)
F) A) and D)

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A survey of 1010 college seniors working towards an undergraduate degree was conducted. Each student was asked, "Are you planning or not planning to pursue a graduate degree?" Of the 1010 surveyed, 658 stated that they were planning to pursue a graduate degree. Construct and interpret a 98% confidence interval for the proportion of college seniors who are planning to pursue a graduate degree.


A) (0.616, 0.686) ; we are 98% confident that the proportion of college seniors who are planning to pursue a graduate degree is between 0.616 and 0.686.
B) (0.621, 0.680) ; we are 98% confident that the proportion of college seniors who are planning to pursue a graduate degree is between 0.621 and 0.680.
C) (0.612, 0.690) ; we are 98% confident that the proportion of college seniors who are planning to pursue a graduate degree is between 0.612 and 0.690.
D) (0.620, 0.682) ; we are 98% confident that the proportion of college seniors who are planning to pursue a graduate degree is between 0.620 and 0.682.

E) B) and C)
F) A) and C)

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Construct a 95% Z-interval or a 95% t-interval about the population mean. Assume the data come from a population that is approximately normal with no outliers. -The heights of 20- to 29-year-old females are known to have a population standard deviation Construct a 95% Z-interval or a 95% t-interval about the population mean. Assume the data come from a population that is approximately normal with no outliers. -The heights of 20- to 29-year-old females are known to have a population standard deviation   inches. A simple random sample of n = 15 females 20 to 29 years old results in the following data:   A)  (65.20, 67.50) ; we are 95% confident that the mean height of 20- to 29-year-old females is between 65.20 and 67.50 inches. B)  (64.98, 67.72) ; we are 95% confident that the mean height of 20- to 29-year-old females is between 64.98 and 67.72 inches. C)  (65.12, 67.58) ; we are 95% confident that the mean height of 20- to 29-year-old females is between 65.12 and 67.58 inches. D)  (64.85, 67.85) ; we are 95% confident that the mean height of 20- to 29-year-old females is between 64.85 and 67.85 inches. inches. A simple random sample of n = 15 females 20 to 29 years old results in the following data: Construct a 95% Z-interval or a 95% t-interval about the population mean. Assume the data come from a population that is approximately normal with no outliers. -The heights of 20- to 29-year-old females are known to have a population standard deviation   inches. A simple random sample of n = 15 females 20 to 29 years old results in the following data:   A)  (65.20, 67.50) ; we are 95% confident that the mean height of 20- to 29-year-old females is between 65.20 and 67.50 inches. B)  (64.98, 67.72) ; we are 95% confident that the mean height of 20- to 29-year-old females is between 64.98 and 67.72 inches. C)  (65.12, 67.58) ; we are 95% confident that the mean height of 20- to 29-year-old females is between 65.12 and 67.58 inches. D)  (64.85, 67.85) ; we are 95% confident that the mean height of 20- to 29-year-old females is between 64.85 and 67.85 inches.


A) (65.20, 67.50) ; we are 95% confident that the mean height of 20- to 29-year-old females is between 65.20 and 67.50 inches.
B) (64.98, 67.72) ; we are 95% confident that the mean height of 20- to 29-year-old females is between 64.98 and 67.72 inches.
C) (65.12, 67.58) ; we are 95% confident that the mean height of 20- to 29-year-old females is between 65.12 and 67.58 inches.
D) (64.85, 67.85) ; we are 95% confident that the mean height of 20- to 29-year-old females is between 64.85 and 67.85 inches.

E) A) and C)
F) A) and B)

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An article a Florida newspaper reported on the topics that teenagers most want to discuss with their parents. The findings, the results of a poll, showed that 46% would like more discussion about the family's financial situation, 37% would like to talk about school, and 30% would like to talk about religion. These and other percentages were based on a national sampling of 535 teenagers. Estimate the proportion of all teenagers who want more family discussions about school. Use a 99% confidence level. Express the answer in the form An article a Florida newspaper reported on the topics that teenagers most want to discuss with their parents. The findings, the results of a poll, showed that 46% would like more discussion about the family's financial situation, 37% would like to talk about school, and 30% would like to talk about religion. These and other percentages were based on a national sampling of 535 teenagers. Estimate the proportion of all teenagers who want more family discussions about school. Use a 99% confidence level. Express the answer in the form   ± E and round to the nearest thousandth. A)  0.37 ± 0.0 54 B)  0.37 ± 0.00 2 C)  0.63 ± 0.00 2 D)  0.63 ± 0.0 54 ± E and round to the nearest thousandth.


A) 0.37 ± 0.0 54
B) 0.37 ± 0.00 2
C) 0.63 ± 0.00 2
D) 0.63 ± 0.0 54

E) C) and D)
F) A) and B)

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Find the t-value. -Find the t-value such that the area left of the t-value is 0.025 with 17 degrees of freedom.


A) -2.11
B) -3.222
C) 2.120
D) 2.110

E) A) and C)
F) A) and B)

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A random sample of 20 electricians is obtained and the monthly income is recorded for each one. A researcher plans to use the bootstrap method with 1000 resamples to obtain a 90% confidence interval for the mean monthly income of all electricians. Which of the following is not true of the resamples?


A) Each resample will be selected from the population.
B) Each resample will be selected from the original sample.
C) Each resample will be of the same size as the original sample.
D) Each resample will be selected with replacement.

E) B) and C)
F) A) and D)

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A

A computer package was used to generate the following printout for estimating the sale price of condominiums in a particular neighborhood. A computer package was used to generate the following printout for estimating the sale price of condominiums in a particular neighborhood.   What assumptions are necessary for any inferences derived from this printout to be valid? A)  The population mean has an approximate normal distribution. B)  The sample variance equals the population variance. C)  The sample was randomly selected from an approximately normal population. D)  All of these are necessary. What assumptions are necessary for any inferences derived from this printout to be valid?


A) The population mean has an approximate normal distribution.
B) The sample variance equals the population variance.
C) The sample was randomly selected from an approximately normal population.
D) All of these are necessary.

E) A) and B)
F) B) and C)

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Find the t-value. -Let Find the t-value. -Let   be a specific value of t. Find   such that the statement is true: P(t ?   )  = 0 .1 where df = 20. A)  -1.328 B)  1.325 C)  1.328 D)  -1.325 be a specific value of t. Find Find the t-value. -Let   be a specific value of t. Find   such that the statement is true: P(t ?   )  = 0 .1 where df = 20. A)  -1.328 B)  1.325 C)  1.328 D)  -1.325 such that the statement is true: P(t ? Find the t-value. -Let   be a specific value of t. Find   such that the statement is true: P(t ?   )  = 0 .1 where df = 20. A)  -1.328 B)  1.325 C)  1.328 D)  -1.325 ) = 0 .1 where df = 20.


A) -1.328
B) 1.325
C) 1.328
D) -1.325

E) A) and D)
F) A) and C)

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A simple random sample of size n < 30 for a quantitative variable has been obtained. Using the normal probability plot, the correlation between the variable and expected z-score, and the boxplot, judge whether a t-interval should be constructed. -n = 10; Correlation = 0.896 A simple random sample of size n < 30 for a quantitative variable has been obtained. Using the normal probability plot, the correlation between the variable and expected z-score, and the boxplot, judge whether a t-interval should be constructed. -n = 10; Correlation = 0.896    A simple random sample of size n < 30 for a quantitative variable has been obtained. Using the normal probability plot, the correlation between the variable and expected z-score, and the boxplot, judge whether a t-interval should be constructed. -n = 10; Correlation = 0.896

A) True
B) False

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In order to set rates, an insurance company is trying to estimate the number of sick days that full time workers at a local bank take per year. Based on earlier studies, they will assumed that s= 2.2 days a) How large a sample must be selected if the company wants to be 98% confident that their estimate is within 1 day of the true mean? b) Repeat part (a) using a 99% confidence interval. Which level of confidence requires a larger sample size? Explain.

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a) 27
b) 33; A 99% confidence ...

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Construct a 95% Z-interval or a 95% t-interval about the population mean. Assume the data come from a population that is approximately normal with no outliers. -Fifteen randomly selected men were asked to run on a treadmill for 6 minutes. After the 6 minutes, their pulses were measured and the following data were obtained: Construct a 95% Z-interval or a 95% t-interval about the population mean. Assume the data come from a population that is approximately normal with no outliers. -Fifteen randomly selected men were asked to run on a treadmill for 6 minutes. After the 6 minutes, their pulses were measured and the following data were obtained:   A)  (94.9, 105.9) ; we are 95% confident that the mean pulse rate of men after 6 minutes of exercise is between 94.9 and 105.9 beats per minute. B)  (95.2, 105.6) ; we are 95% confident that the mean pulse rate of men after 6 minutes of exercise is between 95.2 and 105.6 beats per minute. C)  (93.7, 107.1) ; we are 95% confident that the mean pulse rate of men after 6 minutes of exercise is between 93.7 and 107.1 beats per minute. D)  (94.2, 106.6) ; we are 95% confident that the mean pulse rate of men after 6 minutes of exercise is between 94.2 and 106.6 beats per minute.


A) (94.9, 105.9) ; we are 95% confident that the mean pulse rate of men after 6 minutes of exercise is between 94.9 and 105.9 beats per minute.
B) (95.2, 105.6) ; we are 95% confident that the mean pulse rate of men after 6 minutes of exercise is between 95.2 and 105.6 beats per minute.
C) (93.7, 107.1) ; we are 95% confident that the mean pulse rate of men after 6 minutes of exercise is between 93.7 and 107.1 beats per minute.
D) (94.2, 106.6) ; we are 95% confident that the mean pulse rate of men after 6 minutes of exercise is between 94.2 and 106.6 beats per minute.

E) A) and D)
F) A) and B)

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In a random sample of 26 laptop computers, the mean repair cost was $131 with a standard deviation of $38. Assume the population has a normal distribution. Construct a 95% confidence interval for the population mean, ?. Suppose you did some research on repair costs for laptop computers and found that the standard deviation is In a random sample of 26 laptop computers, the mean repair cost was $131 with a standard deviation of $38. Assume the population has a normal distribution. Construct a 95% confidence interval for the population mean, ?. Suppose you did some research on repair costs for laptop computers and found that the standard deviation is   . Use the normal distribution to construct a 95% confidence interval for the population mean, ?. Compare the results. Round to the nearest cent. . Use the normal distribution to construct a 95% confidence interval for the population mean, ?. Compare the results. Round to the nearest cent.

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( $115.65, $146.35); ( $116.39, $145.61), The t-confidence interval is wider.

In a random sample of 60 dog owners enrolled in obedience training, it was determined that the mean amount of money spent per owner was $109.33 per class. Assuming the population standard deviation of the amount spent per owner is $12, construct and interpret a 95% confidence interval for the mean amount spent per owner for an obedience class.


A) ($106.23, $112.43) ; we are 95% confident that the mean amount spent per dog owner for a single obedience class is between $106.23 and $112.43.
B) ($106.29, $112.37) ; we are 95% confident that the mean amount spent per dog owner for a single obedience class is between $106.29 and $112.37.
C) ($106.74, $111.92) ; we are 95% confident that the mean amount spent per dog owner for a single obedience class is between $106.74 and $111.92.
D) ($106.78, $111.88) ; we are 95% confident that the mean amount spent per dog owner for a single obedience class is between $106.78 and $111.88.

E) C) and D)
F) A) and B)

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A simple random sample of size n < 30 for a quantitative variable has been obtained. Using the normal probability plot, the correlation between the variable and expected z-score, and the boxplot, judge whether a t-interval should be constructed. -n = 14; Correlation = 0.956 A simple random sample of size n < 30 for a quantitative variable has been obtained. Using the normal probability plot, the correlation between the variable and expected z-score, and the boxplot, judge whether a t-interval should be constructed. -n = 14; Correlation = 0.956      A simple random sample of size n < 30 for a quantitative variable has been obtained. Using the normal probability plot, the correlation between the variable and expected z-score, and the boxplot, judge whether a t-interval should be constructed. -n = 14; Correlation = 0.956

A) True
B) False

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What is the best point estimate for p in order to construct a confidence interval for p?


A) What is the best point estimate for p in order to construct a confidence interval for p? A)    B)    C)    D)
B) What is the best point estimate for p in order to construct a confidence interval for p? A)    B)    C)    D)
C) What is the best point estimate for p in order to construct a confidence interval for p? A)    B)    C)    D)
D) What is the best point estimate for p in order to construct a confidence interval for p? A)    B)    C)    D)

E) B) and D)
F) A) and B)

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The general form of a large-sample (1 - ?) 100% confidence interval for a population proportion p is The general form of a large-sample (1 - ?) 100% confidence interval for a population proportion p is   where   =   is the sample proportion of observations with the characteristic of interest. where The general form of a large-sample (1 - ?) 100% confidence interval for a population proportion p is   where   =   is the sample proportion of observations with the characteristic of interest. = The general form of a large-sample (1 - ?) 100% confidence interval for a population proportion p is   where   =   is the sample proportion of observations with the characteristic of interest. is the sample proportion of observations with the characteristic of interest.

A) True
B) False

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A local outdoor equipment store is being sold. The buyers are trying to estimate the percentage of items that are outdated. They will randomly sample among its 100,000 items in order to determine the proportion of merchandise that is outdated. The current owners have never determined their outdated percentage and can not help the buyers. Approximately how large a sample do the buyers need in order to insure that they are 98% confident that the margin of error is within 3%?


A) 1509
B) 648
C) 6033
D) 3017

E) A) and B)
F) None of the above

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A

A confidence interval for p can be constructed using


A) A confidence interval for p can be constructed using A)    ±z   B)    ±     C)  p ± z   D)  p ±    ±z A confidence interval for p can be constructed using A)    ±z   B)    ±     C)  p ± z   D)  p ±
B) A confidence interval for p can be constructed using A)    ±z   B)    ±     C)  p ± z   D)  p ±    ± A confidence interval for p can be constructed using A)    ±z   B)    ±     C)  p ± z   D)  p ±    A confidence interval for p can be constructed using A)    ±z   B)    ±     C)  p ± z   D)  p ±
C) p ± z A confidence interval for p can be constructed using A)    ±z   B)    ±     C)  p ± z   D)  p ±
D) p ± A confidence interval for p can be constructed using A)    ±z   B)    ±     C)  p ± z   D)  p ±    A confidence interval for p can be constructed using A)    ±z   B)    ±     C)  p ± z   D)  p ±

E) A) and B)
F) A) and C)

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