A)
B)
C)
D)
E) None of the above
Correct Answer
verified
Short Answer
Correct Answer
verified
Multiple Choice
A) V > III > II > IV > I
B) II > V > III > I > IV
C) II > III > V > IV > I
D) III > I > V > II > IV
E) V > II > III > I > IV
Correct Answer
verified
Multiple Choice
A) (CH3) 2NH
B) (CH3) 3N
C) (CH3) 2NLi
D) More than one
E) None of the above
Correct Answer
verified
Multiple Choice
A) I > II > III > IV > V
B) III > V > II > I > IV
C) V > II > IV > III > I
D) III > I > V > II > IV
E) V > III > I > II > IV
Correct Answer
verified
Multiple Choice
A) (CH3) 2CH2OH + CH3Na
B) (CH3) 2CH2OH + NaNH2
C) (CH3) 2CH2OH + NaH
D) (CH3) 2CH2OH + H2C=CHNa
E) (CH3) 2CH2OH + CH3CH2ONa
Correct Answer
verified
Multiple Choice
A) i-PrMgBr
B) H2O
C) NaH
D) (i-Pr) 2NLi
E) t-BuOK
Correct Answer
verified
Multiple Choice
A) NaCl
B) H2O
C) NaO2CCH3
D) t-BuOK
E) They would all effectively deprotonate benzoic acid.
Correct Answer
verified
Multiple Choice
A)
B)
C)
D)
E) No reaction
Correct Answer
verified
Multiple Choice
A) i-PrMgBr
B) KH
C) (CH3O) 2CH2Li
D) (i-Pr) 2NLi
E) t-BuOK
Correct Answer
verified
Essay
Correct Answer
verified
View Answer
Multiple Choice
A)
B)
C)
D)
E) None of the above
Correct Answer
verified
Multiple Choice
A) V > III > II > IV > I
B) II > V > III > I > IV
C) V > III > II > I > IV
D) III > I > V > II > IV
E) III > V > II > I > IV
Correct Answer
verified
Multiple Choice
A)
B)
C)
D)
E) All of the above would work.
Correct Answer
verified
Essay
Correct Answer
verified
View Answer
Multiple Choice
A) I > IV > II > V > III
B) II > I > IV > V > III
C) V > III > II > I > IV
D) IV > I > II > V > III
E) IV > II > I > V > III
Correct Answer
verified
Multiple Choice
A)
B)
C)
D)
E) No reaction
Correct Answer
verified
Multiple Choice
A)
B)
C)
D)
E) No reaction
Correct Answer
verified
Multiple Choice
A)
B)
C)
D)
E) No reaction
Correct Answer
verified
Essay
Correct Answer
verified
View Answer
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